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It's like a puzzle, only not fun: My setup consists of a guitar w/midi pickup and two outboard synths controlled by same. All signals (dry guitar, synth 1, synth 2) are routed into a mixer. All signals have their own volume pedal between the source and the mixer. Signal processors are mounted in FX loop of mixer (Aux 1). Whole lotta syrup added here: chorus, detune, delay, doppler panning, flange, harmonizer, sodomizer, transmogrifier, little plastic box that goes "bing!" etc. Looper is mounted thus: mixer's "Tape Out" to looper's input. Output from looper goes into empty channel on mixer. I want to be able to send the signal of my choice (guitar, synth 1, synth 2, or any combination thereof) to the looper. Problem: the looper records wet signal in this configuration. The looper is plugged into the board, and to get the loop back into some semblance of a stereo image I bring up the FX level on that channel AGAIN. Nasty comb filtering, squealing, etc. Solution: run only dry signal to the looper. But HOW? There's three signal sources, and all of them are stereo even when dry (stereo guitar preamp, stereo synths). I can pull half-inserts off of the mono channels... what about a resistive mixer? Hey, that just might work! Patch the three mono dry half-insert signals into a resistive mixer and into the looper, then out of the looper into the board and through the stereo FX bus for some syrup. Anyone got a more rational/elegant/simple/prudent idea than this? I'd love to hear it! Scott Bullerwell tanelorn@dimensional.com Boulder, Colorado, USA